SOLUTION: Find an equation of the tangent line to the curve y=e^x/(1+2e^x ) at the point whose x-coordinate is 0.
Differentiate f(x)=x^x+e^(x-x^3 )-ln〖(ln〖(3x)〗)〗
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Question 1159793: Find an equation of the tangent line to the curve y=e^x/(1+2e^x ) at the point whose x-coordinate is 0.
Differentiate f(x)=x^x+e^(x-x^3 )-ln〖(ln〖(3x)〗)〗
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
if
find tangent point:
tangent point is: (,)
we need a slope of the tangent line, so find derivative:
apply the Quotient Rule
'..........this simplifies to
'
use given to find the slope of the tangent line
'
'
'
'=> the slope of the tangent line is
tangent line is:
..............use tangent point (,) and the slope
and tangent line is:
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