SOLUTION: Find the slope of the line tangent to the following at point, where x=2 f(x)=e^(-0.1x^2+2x-3).

Question 1155282: Find the slope of the line tangent to the following at point, where x=2
f(x)=e^(-0.1x^2+2x-3).

Found 2 solutions by MathLover1, Alan3354:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
Find the slope of the line tangent to the following at point, where
.......if

so, the point is (,) or (,)

compute slope
take first derivative

if

........use point (,)to find

and, tangent is:

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the slope of the line tangent to the following at point, where x=2
f(x)=e^(-0.1x^2+2x-3).
--------------
f(x)=e^(-0.1x^2+2x-3)
---
f'(x) =
Sub 2 for x
===================
---
f'(2) =
f'(2) =
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