SOLUTION: What are the x and y intercepts of these equations 1. f(x)={√x^2, -3≤ x< 0 {x^2 , 0≤ x ≥ 2 2. f(x)={2x, -3≤ x< 0 {1, 0≤ x ≥ 4 3. f(x)={x, 0≤ x< 5 {x-1, -2≤ x

Algebra.Com
Question 1153427: What are the x and y intercepts of these equations
1. f(x)={√x^2, -3≤ x< 0 {x^2 , 0≤ x ≥ 2
2. f(x)={2x, -3≤ x< 0 {1, 0≤ x ≥ 4
3. f(x)={x, 0≤ x< 5 {x-1, -2≤ x ≥ 2

Answer by greenestamps(13215)   (Show Source): You can put this solution on YOUR website!


Note that none of the descriptions of the functions is valid; specifying a range of values as "0≤ x ≥ 2" is meaningless. I will assume that in each example the intended range is like "0≤ x ≤ 2"
1.  on [-3,0);
    on [0,2]

For negative values of x, . On the interval [-3,0), neither x nor -x has the value 0; there are no x- or y-intercepts on that part of the
graph.

For non-negative values of x, on the interval [0,2] both the x and y values are 0 only at x=0. The x- and y-intercepts are both (0,0).

2.  on [-3,0);
    on [0,4]

On the interval [-3,0), x is always negative, so y=2x is always negative; there are no x- or y-intercepts on that part of the graph.

On the interval [0,4], x is clearly 0 at x=0; y is always 1, so it is never 0. This function has an x-intercept at (0,1) and no y-intercept.

3.  on [0,5);
    on [-2,2]

This definition is not valid; the definition results in two different values on the interval [0,2].


RELATED QUESTIONS

What is the domain and range of a graph with these two equations? f(x)=1 {x < 0}... (answered by Boreal)
f(x)=1/1-x find: 1.f'(0) 2.f"(0)... (answered by ewatrrr)
Sketch the graph of f(x) = 2x^2 (x-1)^3 (x+2) I know that the X intercepts are 1, -2, and (answered by lwsshak3)
f(0)=-2, f(x)=f(x-1)+3 (answered by Fombitz)
Find the x- and y-intercepts. If no x-intercepts exist, state so. f(x) = x^2 - 5x - 24 (answered by checkley77)
Given f(x) = x^4-2x^2-15x 1. Find the x-intercepts of the function f(x) I Have This (answered by solver91311)
what are the order pairs for y from these equations Y=2^2x {(-1, ) (0, ), (1, ),... (answered by Tatiana_Stebko)
The polynomial f(x) has degree 3. If f(-1) = 15, f(0)= 0, $f(1) = -5, and f(2) = 12, then (answered by robertb)
The polynomial f(x) has degree 3. If f(-1) = 15, f(0)= 0, f(1) = -5, and f(2) = 12, then... (answered by stanbon)