SOLUTION: A hammer was dropped from the pocket of a constructor from a height of 288 ft building and falls toward the earth in a straight line.In t seconds the hammer drops a distance of s=3

Question 1145824: A hammer was dropped from the pocket of a constructor from a height of 288 ft building and falls toward the earth in a straight line.In t seconds the hammer drops a distance of s=32t^2 ft.
How many seconds after drop does the hammer hit the ground?
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A hammer was dropped from the pocket of a constructor from a height of 288 ft building and falls toward the earth in a straight line.In t seconds the hammer drops a distance of s=32t^2 ft.
How many seconds after drop does the hammer hit the ground?
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s = 32t^2 = 288
t^2 = 9
t = 3 seconds.
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However, I don't think s = 32t^2 is correct on Earth.
Its speed at t seconds = 32t ft/sec, but the distance is 16t^2 feet, usually descending is negative ----> -16t^2 feet.

Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.

The formula s = 32t^2 in your post is INCORRECT.

The correct version is s = 16t^2, where "s" is in feet, "t" is in seconds.

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