SOLUTION: Without using the calculator find 1/(sqrt(3)-tan (20^°))+1/(sqrt(3)+tan(40^°))+1/(sqrt(3)-tan(80^°))

Question 1143526: Without using the calculator find
1/(sqrt(3)-tan (20^°))+1/(sqrt(3)+tan(40^°))+1/(sqrt(3)-tan(80^°))
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Without using the calculator find
1/(sqrt(3)-tan (20^°))+1/(sqrt(3)+tan(40^°))+1/(sqrt(3)-tan(80^°))
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I used a calculator and found it's = sin(60) = cos(30)
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I tried the Trig Identities from Wikipedia, but it got really messy quickly.

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