SOLUTION: the slope of the straight line ehich is both tangent and normal to the cuve 4x^3 = 27y^2 is a) ± 1 b) ±(1/2) c) ± (1/sqrt(2)) d) ± sqrt(2) and find the eq

Question 1143491: the slope of the straight line ehich is both tangent
and normal to the cuve 4x^3 = 27y^2 is
a) ± 1 b) ±(1/2) c) ± (1/sqrt(2)) d) ± sqrt(2)
and find the equation of the lines.
Found 3 solutions by Alan3354, Edwin McCravy, ikleyn:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Not clear what you mean.
--------------
Ikelyn might be correct, but
-----
It is not our job to figure out what you might mean.
It's incumbent upon you to make clear what it is you want to do.

Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!

As you can see from the graph of 4x³ = 27y², the only line that is tangent to the curve and also normal to the curve is the x-axis. The x-axis has equation y = 0 and has slope 0, which is none of the given answers. Is there a mistake in copying something? If so tell me about it in the note form below and I'll get back to you by email. Edwin

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

Edwin / Alan,

the meaning of this assignment is (as I understand it) that the straight line should be tangent to one branch

of the plot (see Edwin's graph) and AT THE SAME TIME be a normal to the other branch.

I myself will not work on it (since I do not see nothing attractive/interesting/educational in it).

But if you are enthusiastic about it, you may try.

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