SOLUTION: Please help me solve this: Suppose AB is the diameter of a circle, where A = (−1, 1) and B = (−4, −5). The equation of the circle is 1. (x + 5/2)^2 + (y + 2)^2 = 45 2.

Question 1142367: Please help me solve this:
Suppose AB is the diameter of a circle, where A = (−1, 1) and B = (−4, −5). The equation of the circle is
1. (x + 5/2)^2 + (y + 2)^2 = 45
2. 4(x + 5/2)^2 + 4(y + 2)^2 = 45
3. (x − 5/2)^2 + (y − 2)^2 = 45
4. 4(x − 5/2)^2 + 4(y − 2)^2 = 45
5. 2(x + 5/2)^2 + 2(y + 2)^2 = sqrt (45)
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!

The center of the circle is the midpoint of the diameter AB.

The radius of the circle is half the length of the diameter AB.

The equation of a circle with center (h,k) and radius r is, in standard form,

(1) What are the coordinates of the center?
(2) What is the radius?
(3) What is the equation?
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