SOLUTION: Find the center of the circles tangent to 5x-2y-1=0 at 1,2 with a radius of 3

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Question 1141543: Find the center of the circles tangent to 5x-2y-1=0 at 1,2 with a radius of 3

Found 2 solutions by MathLover1, Edwin McCravy:
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!
If the equation of the circle is
where (,) is the center, we can find the gradient by differentiation:

At (,) the gradient is given by

Therefore

Point (,) lies on the circle:

The gradient of the line is given by
:



This gradient is tangent to the circle, so






So,











=±
=(±)=±=±

So we have two circles with different centers:

(,) and (,)
or approximately
(,) and (, )

equations:

and




Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
Let the center of the circle be (h,k). 
   

The red line is the given line
5x-2y-1 = 0.  The green line is the line perpendicular to it.

Since 5x-2y-1 = 0 solved for y is , its slope
is  so the green line has slope  and since it
goes through (1,2) we use the point slope formula and get the equation:






 <-- equation of green line.

Since (h,k) lies on the green line,



Next we use the formula for the distance from a point (x1,y1) to the line
Ax+By+C=0, which is



and the distance from (h,k) must be ±3 units to the line 5x-2y-1=0, so we have









We solve the system:



using the + and then the -, the two centers are

(h,k) = (-1.785439973,3.114172029)

and

(h,k) = (3.785430073,0.8858279709)

Edwin

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