SOLUTION: a motorist travelling at constant speed leaves A at 11 00 intending to arrive B , 100km away at 1300 . half an hour later one of the tyres are punctured ands he is delayed for 18 m

Question 1134823: a motorist travelling at constant speed leaves A at 11 00 intending to arrive B , 100km away at 1300 . half an hour later one of the tyres are punctured ands he is delayed for 18 mins . how fast must he then proceed in order to reach B on time ? at what time will he meet a cyclist who leaves town B at 11 45 for A ., travelling at a contant speed of 20 km/h ? make a distancwe time graph
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = motorist's initial constant speed in km/hr
In 1/2 hr, he travels km
--------------
He needs to make deadline of 2 hrs to get to B
After the 1/2 hr of travel, he loses 18 min, so now
he needs to get to B from location of puncture
in hrs
--------------------------------
The distance he has to travel is
I can say:

--------------------------------------
Looking at the total time, I can say:

km/hr
and

km/hr answer
-------------------------------------
check answer:

----------------------

km
and

OK
----------------------------
That's as far as I can go due to time

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

a motorist travelling at constant speed leaves A at 11 00 intending to arrive B , 100km away at 1300 . half an hour later one of the tyres are punctured ands he is delayed for 18 mins . how fast must he then proceed in order to reach B on time ? at what time will he meet a cyclist who leaves town B at 11 45 for A ., travelling at a contant speed of 20 km/h ? make a distancwe time graph

The other person's answer of 31.25 km/h can't be correct and just doesn't make sense.

With a time of 2 (1300 - 1100) hours to cover a distance of 100 km, his planned average-speed was for the trip
At , distance covered was:

Since he has 1.2 (2 - .5 - .3) hours to cover 75 (100 - 25) km, then his speed MUST be: .
**NOTE: He MUST travel FASTER than his planned average-speed in order to make it on time.
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