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Q: Write equation of line through (2,-3) parallel to 2x-3y=0. Write equation is standard form.
What I did:
2x-3y=0 <=== I found a slope o
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Question 1122461: Need answer confirmation please.
Q: Write equation of line through (2,-3) parallel to 2x-3y=0. Write equation is standard form.
What I did:
2x-3y=0 <=== I found a slope of 2/3
Then:
y-(-3)=2/3(x-2)
y+3=2/3(x-2)
Then to Standard form:
y+3=2/3x-4
y+3-3=2/3x-4-3
y=2/3x-7
From there:
I subtracted -2/3 from both sides and arrived at: -2/3x+y=-7
Is this correct?
Thank you!
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Your answer in italics as far as you were correct:
2x-3y=0 <=== I found a slope of 2/3
Then:
y-(-3)=2/3(x-2)
y+3=2/3(x-2)
Then you started to go awry:
Your next step should have been to get rid of the fractional slope by multiplying by the denominator, namely 3:
)
)
Distribute:
Put the variable terms in the LHS and the constants in the RHS
Collect
I like my lead coefficient to be positive, so:
John
My calculator said it, I believe it, that settles it
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