SOLUTION: Question is not from the text. Could you please tell me how to set up the following problem? How many ounces of pure gold must be added to five ounces of something that is 1% gol

Question 111953: Question is not from the text.
Could you please tell me how to set up the following problem?
How many ounces of pure gold must be added to five ounces of something that is 1% gold in order that the mixture is 6% gold?
Thanks!
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=amount of pure gold needed
Now we know that the amount of pure gold added (x) plus the amount of pure gold in the 1% alloy (0.01)*5 has to equal the amount of pure gold in the final mixture (5+x)*0.06. So our equation to solve is:
x+0.01*5=0.06(5+x) get rid of parens and simplify
x+0.05=0.3+0.06x subtract 0.06x and also 0.05 from both sides
x-0.06x+0.05-0.05=0.3-0.05+0.06x-0.06x collect like terms
0.94x=0.25
x=0.266 oz
0.266+0.05=0.06(5.266)
0.316~~~0.316

Hope this helps---ptaylor

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