SOLUTION: A line passing through (–6, –5) and (–1, y) is perpendicular to a line with slope -5/13 . Find the value of y.

Algebra.Com
Question 111717: A line passing through (–6, –5) and (–1, y) is perpendicular to a line with slope -5/13 . Find the value of y.
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
A line passing through (–6, –5) and (–1, y) is perpendicular to a line with slope -5/13 . Find the value of y.

to find the value of , you first need to use the given data that this line is to a line with slope , so you can calculate a slope for your line
we know that if the lines are perpendicular, then :
find for line:









….this is a slope of a line passing through (–6, –5) and (–1, y)

we can calculate using this formula:





…………………………move to the left
………multiply both sides by
………
………
………,,,,,,,,,,,,,,,,,,
Solved by pluggable solver: Finding the Equation of a Line
First lets find the slope through the points (,) and (,)


Start with the slope formula (note: (,) is the first point (,) and (,) is the second point (,))


Plug in ,,, (these are the coordinates of given points)


Subtract the terms in the numerator to get . Subtract the terms in the denominator to get



So the slope is







------------------------------------------------


Now let's use the point-slope formula to find the equation of the line:




------Point-Slope Formula------
where is the slope, and (,) is one of the given points


So lets use the Point-Slope Formula to find the equation of the line


Plug in , , and (these values are given)



Rewrite as



Rewrite as



Distribute


Multiply and to get

Subtract from both sides to isolate y


Combine like terms and to get (note: if you need help with combining fractions, check out this solver)



------------------------------------------------------------------------------------------------------------

Answer:



So the equation of the line which goes through the points (,) and (,) is:


The equation is now in form (which is slope-intercept form) where the slope is and the y-intercept is


Notice if we graph the equation and plot the points (,) and (,), we get this: (note: if you need help with graphing, check out this solver)


Graph of through the points (,) and (,)


Notice how the two points lie on the line. This graphically verifies our answer.







RELATED QUESTIONS

A line passing through (–6, –5) and (–1, y) is perpendicular to a line with slope -5/13 . (answered by checkley71)
A line passing through (–6, –5) and (–1, y) is perpendicular to a line with slope -5/13 . (answered by ankor@dixie-net.com)
A line passing through (–6, –5) and (–1, y) is perpendicular to a line with slope .... (answered by Edwin McCravy)
A line passing through (–6, –5) and (–1, y) is perpendicular to a line with slope .... (answered by Edwin McCravy)
Line passing through (5,-6) and (-9,4) is perpendicular to a line with a slope 14/5. Find (answered by checkley71)
Please help. find the value of y if a line passing through (2,3) and (5,y) is... (answered by HyperBrain)
A line passing through (5,-8) and (9,y) is perpendicular to a line with slope -4/9.... (answered by ankor@dixie-net.com)
A line passing through(2,3) and (5,y) is perpendicular to a line with a slope 3/4. What... (answered by nerdybill,jojo14344)
A line passing through (-8, 2) and (-1,y) is perpendicular to a line with slope -7/5.... (answered by bucky)