SOLUTION: I need to graph these linear equations the more i try the more i get confussed. y=5x-2 3x-1=5x-y y=[x]+3 x+2=2x-1 thank you very much

Question 111476: I need to graph these linear equations the more i try the more i get confussed.

y=5x-2

3x-1=5x-y
y=[x]+3

x+2=2x-1 thank you very much
Answer by BrittanyM(80) (Show Source): You can put this solution on YOUR website!
For the first problem, y=5x-2, we have to plot our first point at (0, -2) because this is our y-intercept, or "b". Next, we have to find the slope, or "m". This number is the coefficient of the x variable. And in this equation, it is 5.
y=mx+b
Now that we know the slope and the y-intercept, as modeled in the general equation above, we can graph. As I mentioned earlier, our first point is the y-intercept at (0, -2). From this point, we can count up and over using the slope. This is "rise over run". In this particular equation, that is 5 up and 1 over. And since the slope is positive, over is to the right.
We have to get the mext equation into the y=mx+b form.
3x-1=5x-y
y-1=2x
y=2x+1
You would follow the same steps as we went through in order to graph the first equation. In this equation, the y-intercept is 1, and the slope is 2.
I'm asuming that the next equation is an absolute value problem. But since the absolute value brackets are nowhere to be found on the keyboard, we will use standard brackets to indicate absolute values. :)
All the absolute value means is that whatever number you plug into the brackets, whether it be positive or negetive, the outcome will be positive.
EX:
[-2]=2
y=[x]+3
The y-intercept is 3, and the slope is one. The trick to absolute value problems is the never allow the y coordinate to be negetive. Because of this, your finished graph should look like a "V".
For our last equation, x+2=2x-1
We need to isolate the x since there is no y.
x=3
This graph is going to be a horizontal line at 3 on the x-axis. This shows that for all values, x is 3.
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