SOLUTION: solve : floor(x) -x =-0.2 find value of a if i^(a!)=I^84 :i^2=-1

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Question 1106948: solve : floor(x) -x =-0.2
find value of a if i^(a!)=I^84 :i^2=-1
Found 3 solutions by ankor@dixie-net.com, ikleyn, 7022:
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
What is "floor"?
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
There are infinitely many solutions.

For any integer  n  (positive,  negative or zero)  the number  x = n + 0.2  is the solution.

There are NO other solutions.

For example,  the numbers  0.2,  1.2,  5.2,  -0.8,  -12.8  are the solutions.


=============
Regarding the function floor(x), see this Wikipedia article 
    https://en.wikipedia.org/wiki/Floor_and_ceiling_functions

Its definition is THIS: 

    In mathematics, the floor function is the function that takes as input a real number x and gives as output the greatest integer 
    that is less than or equal to  x.


Answer by 7022(2)   (Show Source): You can put this solution on YOUR website!

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