SOLUTION: Acute isosceles triangle ABC has vertices A(-2,-1), B(3,13), with point C on the line x=-7. If AB=BC, then find the coordinates of C.
Algebra.Com
Question 1100224: Acute isosceles triangle ABC has vertices A(-2,-1), B(3,13), with point C on the line x=-7. If AB=BC, then find the coordinates of C.
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!
If AB=BC, then (AB)^2 = (AC)^2; so we can solve the equation that says the squares of the distances are equal.
Using the distance formula on AB, we find
Using the distance formula on BC, we find
Then
Point C is (-7,2)
RELATED QUESTIONS
Acute isosceles triangle ABC has vertices A(-2,-1), B(3,13), with point C on the line x=... (answered by greenestamps)
I NEED HELP. PLEASE HELP ME ASAP. THANKS BEFORE :)
1) The straight line with equation... (answered by richard1234)
An isosceles triangle ABC has its vertices on a circle. If AB| = 13 cm, |BC| = 13 cm and. (answered by ikleyn)
I need major help on how to answer these questions and what they are. Here is the info...
(answered by Fombitz)
Triangle ABC is isosceles with AB=BC=10 units and apex B (1,8). The base AC is parallel... (answered by KMST)
3) show that if A-B-C and B-C-D,then A-B-D and A-C-D
4)Given aline m with coordinate... (answered by 90089)
find the measure of each side of isosceles ABC with AB=BC if AB=4y, BC=3y+2, and AC=3y
(answered by ewatrrr)
Could someone outline a strategy for solving the following problem?
*Let \( \triangle... (answered by CPhill)
In an isosceles triangle labelled ABC, with BC as the base, and AB as the hypotenuse, and (answered by greenestamps)