SOLUTION: 2x + 1 < –5 or 2 + 3x > 11

Algebra.Com
Question 1100147: 2x + 1 < –5 or 2 + 3x > 11
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.
These two inequalities are connected by the conjunction term "OR".
It means that you should solve each inequality SEPARATELY, and then take a UNION of the solution domains.

This UNION will be the final solution.
So I will implement it in two steps.

1.  2x + 1 < -5  is equivalent to  2x < -5 -1,   or  2x < -6,   or x < -3.


2.  2 + 3x > 11 is equivalent to   3x > 11 - 2,  or  3x > 9,   or  x > 3.


Answer.  The solution is the union  (,) U (,).


RELATED QUESTIONS

Solve 3x - 4 ≤ 2 or 2x + 11 ≥... (answered by tommyt3rd)
5(2x-1)-2x=11+2(3x-3) (answered by fractalier)
3x+1<-2 or... (answered by jim_thompson5910)
6x-2x+11=-5... (answered by checkley71)
2| 3x + 1 | - 5 =... (answered by addingup,josgarithmetic)
3x+5(2x-11)=2+9x (answered by orca)
3x+2<=-1 or... (answered by lwsshak3)
3x+5=2x-11 (answered by checkley77)
Solve 3x + 1 <_ -2 or 2x + 3 >_... (answered by RAY100)