SOLUTION: graph f(x)=-Ix+4I-3 I I are absoulte value signs.

Question 1099138: graph f(x)=-Ix+4I-3
I I are absoulte value signs.
Found 2 solutions by Fombitz, ikleyn:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
For next time, you can just use f(x)=-abs(x+4)-3.
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Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
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The correct graph is below:

Plot y = -|x+4)| - 3
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