Question 1095871: Please help simplify the following:
((6x^2)/ (x^2+2x+4))/ ((x^3-8) /(-6x+12))
Thank you Found 2 solutions by Boreal, MathTherapy:Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website! ((6x^2)/ (x^2+2x+4))/ ((x^3-8) /(-6x+12))
The numerator becomes 6x^2/(x^2+2x+4)
The denominator becomes -(x-2)(x^2+2x+4)/(6x-12), because if I put a negative sign out front, one of the two terms may be negated without changing the fraction.
This becomes -(x-2)/(x^2+2x+4)/6(x-2). That becomes -(1/6(x^2+2x+4)
The trinomials cancel since they are both denominators.
This becomes 6x^2/-(1/6)=-36x^2
Let x=3
the original is 54/19 divided by 19/-6
That is -324
-36x^2=-324 Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Please help simplify the following:
((6x^2)/ (x^2+2x+4))/ ((x^3-8) /(-6x+12))
=====> =====> ------ Factoring numerator and denominator ======>