SOLUTION: 3<2x+11<17 -- I understand how to solve for x, but I do not know how to graph on a number line since x appears twice with two numbers.

Question 10944: 3<2x+11<17 -- I understand how to solve for x, but I do not know how to graph on a number line since x appears twice with two numbers.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Think of this (it's a DOUBLE inequality) as an inequality in three parts.
For example, if you had a
Now if you have three children in the family, if you do something for one, you need to do it for ALL three. In the case of 3<2x+11<17 , you are saying that 3 is the smallest (youngest), 17 is the largest (oldest), and the 2x+11 represents something in between.

The name of the game with 3<2x+11<17 is to get the x by itself in the middle. In order to do this, you must eliminate the 11 with a negative 11, and undo the 2 which is multiplied times x by DIVIDING by 2. However, whatever you do, you must do to EACH of the three parts:

Subtract 11 from each part:
3<2x+11<17
3-11 <2x+11-11<17 -11

-8< 2x < 6

Now to undo the 2, divide each of the three parts by 2:

This means in words that x must be between -4 and 3.

R^2 at SCC
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