SOLUTION: y = -1/2x^2
graph the parabola, plot the vertex and four additional points, two on each side of the vertex.
Algebra.Com
Question 1091736: y = -1/2x^2
graph the parabola, plot the vertex and four additional points, two on each side of the vertex.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
y=-(1/2)x^2
vertex has x value of -b/2a. But there is no b, so vertex has x value of 0, and y value of 0. The origin.
when x=1 or -1, y=-1/2
when x=2 or -2, y=-2
RELATED QUESTIONS
Graph the parabola:
y=-x^2-10x-20
Plot the vertex and four additional points, two... (answered by josgarithmetic)
Graph the parabola: y=(x+2)^2-4
To graph the parabola, plot the vertex and four... (answered by josgarithmetic,MathTherapy)
Graph the parabola y=-5/4x^2
To graph the parabola, plot the vertex and four additional... (answered by Fombitz)
Graph the parabola:
Y=(x+1)^2-1
To graph the parabola, plot the vertex and four... (answered by nerdybill)
y= (x-4)2(2=to the second power)-1. I have to graph the parabola and four additional... (answered by ewatrrr)
Can you help me graph a parabola and 4 additional points. two on each side of the vertex. (answered by ewatrrr)
Graph the parabola y=(x+1)^2+4. Give five points; the vertex and two on each side of the... (answered by lynnlo)
Graph parabola show the vertex and at least two points on either side of the vertex.
y (answered by richwmiller)
How do i graph this equation?
y=4/3x2+8/3x-8/3
Please give me the Vertex and 4... (answered by solver91311)