SOLUTION: 1. What is the line parallel to y=6/7x+11/7 through point (0,2)? 2. What is the line perpendicular to y=0x+3 through point (-3,4)? 3. Use synthetic division to find the value of

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Question 1079285: 1. What is the line parallel to y=6/7x+11/7 through point (0,2)?
2. What is the line perpendicular to y=0x+3 through point (-3,4)?
3. Use synthetic division to find the value of the function when x=2 where f(x)=5x^4-12x^2+2x-8
4. Factor (x-1)(x^3+2x^2+3x+2)completely
Answer by josgarithmetic(39621)   (Show Source): You can put this solution on YOUR website!
1. What is the line parallel to y=6/7x+11/7 through point (0,2)?
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2. What is the line perpendicular to y=0x+3 through point (-3,4)?
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The reason is that the given line is horizontal; and the line perpendicular to it must be vertical, so no slope, and this must run through x=-3, and will include all y values.


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3. Use synthetic division to find the value of the function when x=2 where f(x)=5x^4-12x^2+2x-8
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2    |    5    0    -12    2    -8
     |
     |         10   20     16   36
     |__________________________________
         5    10     8    18   28


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