SOLUTION: Given 2(x-1)^2+3(y+1)^2=52 the coordinates of the center are A. (-1,1) B (3,-2) C, (-2,3) D, (1,-1)

SOLUTION: Given 2(x-1)^2+3(y+1)^2=52 the coordinates of the center are A. (-1,1) B (3,-2) C, (-2,3) D, (1,-1)

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Question 1070753: Given 2(x-1)^2+3(y+1)^2=52 the coordinates of the center are
A. (-1,1)
B (3,-2)
C, (-2,3)
D, (1,-1)

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Given 2(x-1)^2+3(y+1)^2=52 the coordinates of the center are (h,k)
==========
2(x-h)^2 + 3(y-k)^2 = 52
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