SOLUTION: Find the equation of the line that is perpendicular to the line 2x+3y=-17 and which passes through point (2,5)

Question 1068684: Find the equation of the line that is perpendicular to the line 2x+3y=-17 and which passes through point (2,5)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
2x+3y=-17
3y=-2x-17
y=(-2/3)x-17/3. That slope is -2/3
The line perpendicular to that has a slope that is the negative reciprocal, or 3/2
point-slope y-y1=m(x-x1) m is slope and (x1,y1) is point.
y-5=(3/2)(x-2)
y-5=(3/2)x-3
y=(3/2)x+2

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