SOLUTION: The co ordinates of the end points of a line segment PQ are P(3,7) and Q(11,-6). Find the coordinates of the point R on the y-axis such that PR=QR

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Question 1060124: The co ordinates of the end points of a line segment PQ are P(3,7) and Q(11,-6). Find the coordinates of the point R on the y-axis such that PR=QR
Found 3 solutions by Fombitz, ikleyn, MathTherapy:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
So R would be the midpoint of PQ.
The midpoint is the average of the x and y values,


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Q:(,)
Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
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The co ordinates of the end points of a line segment PQ are P(3,7) and Q(11,-6). Find the coordinates of the point R on the y-axis such that PR=QR
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The points in the y-axis are {R = (0,y)}.

The distance from R to P is   = .

The distance from R to Q is   = .


The condition  |PR| = |QR|  is

 = .

Square both sides to get

9 + (y-7)^2 = 121+(y+6)^2.

9 + y^2 - 14y + 49 = 121 + y^2 + 12y + 36,

-99 = 26y.

y = .


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
The co ordinates of the end points of a line segment PQ are P(3,7) and Q(11,-6). Find the coordinates of the point R on the y-axis such that PR=QR
Fact: The given points are located in the 1st and 4th quadrants

Fact: The x-coordinate of R is 0

y coordinate, when found, is: , so coordinates of R are:  

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