SOLUTION: Find the area of the region enclosed by the graph of the equation $x^2 + y^2 = 4x + 6y+13$. Thanks!

Question 1059944: Find the area of the region enclosed by the graph of the equation $x^2 + y^2 = 4x + 6y+13$.
Thanks!
Answer by ikleyn(52847) (Show Source): You can put this solution on YOUR website!
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Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y + 13.
Thanks!
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The equation represents a circle.
All we need to do is to find its radius.
For it, let us reduce the equation to the standard form.
Apply the completing the square method:

 = .  ===>

 = 13.

 = 13.

 = 13 + 4 + 9.

 = 26.

The figure is the circle of the radius r = .

Its area is  =  = 3.14*26.

Solved.

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