SOLUTION: Find the standard form of the equation of the circle which passes through the point (4, -5) and center at (-2,3)

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Question 104936: Find the standard form of the equation of the circle which passes through the point (4, -5) and center at (-2,3)
Found 2 solutions by Fombitz, edjones:
Answer by Fombitz(13828) About Me  (Show Source):
You can put this solution on YOUR website!
Find the standard form of the equation of the circle which passes through the point (4, -5) and center at (-2,3)
The standard form of a circle centered at (h,k) is
%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2
We can calculate R using the center and the point provided.
The distance between the two points equals the radius.
D%5E2=R%5E2=%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2 Distance = Radius
%28x-%28-2%29%29%5E2%2B%28y-3%29%5E2=%284-%28-2%29%29%5E2%2B%28-5-3%29%5E2 PLug in all the values
%28x%2B2%29%5E2%2B%28y-3%29%5E2=%286%29%5E2%2B%28-8%29%5E2 Simplify.
%28x%2B2%29%5E2%2B%28y-3%29%5E2=100 Final answer.
Circle with center (-2,3) and passing through (4,-5) has a radius of 10.

Answer by edjones(7569) About Me  (Show Source):
You can put this solution on YOUR website!
(x-a)^2+(y-b)^2=r^2 where x=4, y=-5, a=-2, b=3
(4+2)^2+(-5-3)^2=r^2
36+64=r^2
r^2=100
r=10
Ed