# SOLUTION: Find the standard form of the equation of the circle which passes through the point (4, -5) and center at (-2,3)

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 Question 104936: Find the standard form of the equation of the circle which passes through the point (4, -5) and center at (-2,3)Found 2 solutions by Fombitz, edjones:Answer by Fombitz(13828)   (Show Source): You can put this solution on YOUR website!Find the standard form of the equation of the circle which passes through the point (4, -5) and center at (-2,3) The standard form of a circle centered at (h,k) is We can calculate R using the center and the point provided. The distance between the two points equals the radius. Distance = Radius PLug in all the values Simplify. Final answer. Circle with center (-2,3) and passing through (4,-5) has a radius of 10. Answer by edjones(7569)   (Show Source): You can put this solution on YOUR website!(x-a)^2+(y-b)^2=r^2 where x=4, y=-5, a=-2, b=3 (4+2)^2+(-5-3)^2=r^2 36+64=r^2 r^2=100 r=10 Ed