SOLUTION: Find the standard form of the equation of the circle which passes through the point (4, -5) and center at (-2,3)

Question 104936: Find the standard form of the equation of the circle which passes through the point (4, -5) and center at (-2,3)
Found 2 solutions by Fombitz, edjones:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Find the standard form of the equation of the circle which passes through the point (4, -5) and center at (-2,3)
The standard form of a circle centered at (h,k) is

We can calculate R using the center and the point provided.
The distance between the two points equals the radius.
Distance = Radius
PLug in all the values
Simplify.
Final answer.
Circle with center (-2,3) and passing through (4,-5) has a radius of 10.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
(x-a)^2+(y-b)^2=r^2 where x=4, y=-5, a=-2, b=3
(4+2)^2+(-5-3)^2=r^2
36+64=r^2
r^2=100
r=10
Ed

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