SOLUTION: the radius (R) and the center (C) of this circle x^2+y^2+6x-4y+3=0 are ?

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Question 1044636: the radius (R) and the center (C) of this circle x^2+y^2+6x-4y+3=0 are ?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39625)   (Show Source): You can put this solution on YOUR website!


Complete The Square for the x and the y. Keep going, putting into standard form, and read the desired values. You need to use the terms, 9 for the x and 4 for the y.
Answer by ikleyn(52847)   (Show Source): You can put this solution on YOUR website!
.
the radius (R) and the center (C) of this circle x^2+y^2+6x-4y+3=0 are ?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

Complete the square separately in "x" and "y":

 = 0   --->

( + __) - __ + ( + __) - __ + 3 = 0,

 = 0,

 = 0,

 = 9 + 4 - 3,

 = 10.

The circle with the center at  (-3,2)  of the radius  .


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