SOLUTION: Find the equation of a line parallel to 3x+4y=7 intersect the positive x axis and positive y axis so that the triangle formed by the line and these axes has an area of 6. Than

Question 1033772: Find the equation of a line parallel to 3x+4y=7 intersect the positive x axis and positive y axis so that the triangle formed by the line and these axes has an area of 6.

Thank you in advanced!
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
The line would have to have the form 3x+4y = k for some undetermined constant k > 0, as wanted.
The x-intercept of this line is k/3, while its y-intercept is k/4.
The area is thus
==> ==> k = 12.
Therefore the equation of the line is 3x+4y=12.

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