SOLUTION: 13-(2c+2) >or= 2(c+2)+3c
How do you write this in set builder and interval notation
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Question 1030937: 13-(2c+2) >or= 2(c+2)+3c
How do you write this in set builder and interval notation
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
your equation is 13 - (2c+2) >= 2(c+2) + 3c
i think you have to solve it first.
you will get c <= 1
in interval notation that would be c = (- infinity, 1]
that means that minus infinity is smaller than c which is smaller than or equal to 1
the symbol ( on the left means c is greater than minus infinity.
the symbol ] on the right means that c is less than or equal to 1.
here's some references.
the first is on interval notation.
http://www.coolmath.com/algebra/07-solving-inequalities/03-interval-notation-01
the second is on set builder notation.
http://www.coolmath.com/algebra/07-solving-inequalities/02-set-builder-notation-01
in set builder notation, your answer would look like this:
{ c | c <= 1 }
this means the set of all c's such that c <= 1
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