SOLUTION: Zmax=8x1+16x2 subject to x1+x2<200 3x1+6x2<900 x2=125 x1 x2>0

SOLUTION: Zmax=8x1+16x2 subject to x1+x2<200 3x1+6x2<900 x2=125 x1 x2>0

Algebra.Com

Question 1027394: Zmax=8x1+16x2
subject to
x1+x2<200
3x1+6x2<900
x2=125
x1 x2>0
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Your constraints are given so that the lines are not included as part of the solution.
When you substitute

.
.

.
.
So then,

Since you don't have an equal sign, you can't get an exact value for the maximum Z value.
You can state,

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