SOLUTION: FWI: this is Algebra 2 not Algebra 1. I put it in here only because there wasn't a designated topic to put this under and it kind of but not really belong here...so ehh... Sorry f

Question 1021496: FWI: this is Algebra 2 not Algebra 1. I put it in here only because there wasn't a designated topic to put this under and it kind of but not really belong here...so ehh... Sorry for this inconvenience.
Describe how the vertex form of quadratic functions is similar to the form f(x)= a(x-h)^3 +k for cubic functions.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The cubic function has a local maximum (a=positive) or minimum (a is negative) at x=h.
The derivative of this function is 3a(x-h)^2, so the rate of change of the function is a quadratic, and at x=h the rate of change is 0, the same as the instantaneous rate of change of the quadratic function is 0 at the vertex. The final graph shows what is happening at x=3 and y=4. The last graph is negative a.

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