SOLUTION: Hello, How do I write an equation for this: Perpendicular to the graph of 4x-y=12 and passes through (8,2) Thank you

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Question 101509: Hello,

How do I write an equation for this:

Perpendicular to the graph of 4x-y=12 and passes through (8,2)

Thank you

Found 2 solutions by elima, MathLover1:
Answer by elima(1433)   (Show Source): You can put this solution on YOUR website!
Perpendicular to the graph of 4x-y=12 and passes through (8,2)
The slopes of Perpendicular lines are negative reciprocals;
first lets put the equation in standard form;
4x-y=12
-y=-4x+12
y=4x-12; so the slope of this line is 4;
The slope of the perpendicular line is
Now that we have the slope we use the point-slope form to find the equation;




; equation of perpendicular line
:)

Answer by MathLover1(20855)   (Show Source): You can put this solution on YOUR website!
From we can see that slope
Therefore the perpendicular line has slope
If you use , you will have:
now you can simplify it




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