SOLUTION: Write the equation of the line that passes through point (–6, –2) with a slope of 0.

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Question 101089: Write the equation of the line that passes through point (–6, –2) with a slope of 0.
Found 2 solutions by tutorcecilia, edjones:
Answer by tutorcecilia(2152)   (Show Source): You can put this solution on YOUR website!
(–6, –2) with a slope of 0.
Use the formula for the slope-intercept equation of a line:
y=mx+b
Plug-in the values:
-2=(0)(-6)+b
Solve for the b=term:
-2=-6+b
-2+6=b
4=b
Plug-in the values of the y=intercept and the slope:
y=(0)x+4
or
y=4 (a straight horizontal line passing through y=4 for all values of x)

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: FIND a line by slope and one point

What we know about the line whose equation we are trying to find out:

  • it goes through point (-6, -2)

  • it has a slope of 0



First, let's draw a diagram of the coordinate system with point (-6, -2) plotted with a little blue dot:



Write this down: the formula for the equation, given point and intercept a, is

(see a paragraph below explaining why this formula is correct)

Given that a=0, and , we have the equation of the line:



Explanation: Why did we use formula ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (, ) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (, ): Here, we know a, , and , and do not know b. It is easy to find out: . So, then, the equation of the line is: .

Here's the graph:




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