SOLUTION: What is each piece of information telling about the function exactly? The function has these properites: f(0) = 0 f'(1) = 0 lim x->∞ f(x) = 0 lim x->-∞ f(x) = 0

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Question 1001667: What is each piece of information telling about the function exactly?
The function has these properites:
f(0) = 0
f'(1) = 0
lim x->∞ f(x) = 0
lim x->-∞ f(x) = 0
lim x->-1 f(x) = ∞
f'(x)>0 on (-∞,-1)U(1,∞)
f'(x)<0 on (-1,1)
f"(x)>0 on (-∞,-1)U(-1,3)
f"(x)<0 on (3,∞)
Please explain these have an exam and I need to know how to construct a graph from this information.
Thank you

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

StatementTranslation
f(0) = 0The point (0,0) is on the graph of f(x)
f'(1) = 0The slope of the tangent line at x = 1 is m = 0. This tangent line is horizontal
lim x->∞ f(x) = 0There is a horizontal asymptote at y = 0
lim x->-∞ f(x) = 0There is a horizontal asymptote at y = 0
lim x->-1 f(x) = ∞There is a vertical asymptote at x = -1
f'(x)>0 on (-∞,-1)U(1,∞)Function f(x) is increasing when x < -1 or when x > 1
f'(x)<0 on (-1,1)Function f(x) is decreasing when -1 < x < 1
f"(x)>0 on (-∞,-1)U(-1,3)Function f(x) is concave up when x < -1 or when -1 < x < 3
f"(x)<0 on (3,∞)Function f(x) is concave down when x > 3

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