SOLUTION: Hello I have a couple of questions I need you to do for me! Thanks!! 1. Find both the x-intercept and the y-intercept of the line given by the equation 3x+7y-11=0 2. What

Question 100001: Hello I have a couple of questions I need you to do for me! Thanks!!
1. Find both the x-intercept and the y-intercept of the line given by the equation
3x+7y-11=0
2. What is the slope of the line ?
4x-3y=-2
3. The cost of water use (in dollars) is a linear function of the amount of water used (in hundreds of cubic feet, HCF), as shown in the figure below. The cost for using 14 HCF of water is $31.40 , and the cost for using 47 HCF is $ 82.55 . What is the cost for using 26 HCF of water?

4. Carmen is a software saleswoman. Carmen's monthly salary is plus an additional for every copy of Math is Fun she sells.
Let S represent Carmen's monthly salary (in dollars), and let N represent the number of copies of Math is Fun that she sold. Write an equation relating to S to N , and then graph your equation.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1. Find both the x-intercept and the y-intercept of the line given by the equation
3x+7y-11=0
---------
x-intercept: let y = 0 and solve for x: x=11/3
y-intercept: let x = 0 and solve for y: y = 11/7
-------------------------------------------------------
2. What is the slope of the line ?
4x-3y=-2
slope = 4/3
-----------------------------------------
3. The cost of water use (in dollars) is a linear function of the amount of water used (in hundreds of cubic feet, HCF), as shown in the figure below. The cost for using 14 HCF of water is $31.40 , and the cost for using 47 HCF is $ 82.55 . What is the cost for using 26 HCF of water?
-------
You have two points: (14,31.40),(47,82.55)
slope = [82.55-31.40]/[47-14] = 1.55
Form of the equation: cost = slope(HCF count) + b
31.40 = 1.55*14 + b
b = 9.7
----------
EQUATION:
cost = 1.55(HCF count) 9.7
---------------
If HCF count = 26 then:
price = 1.55*26+9.7
price = 50
===================
Cheers,
Stan H.

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