# SOLUTION: GRAPH THE LINE: Y-5=3X. YOU MUST SHOW A TABLE WITH AT LEAST THREE X-Y VALUES. LABEL TH AXES AND SOME "HASH" MARKS. I GOT THESE BUT I STILL DON'T UNDERSTAND HOW TO DO THIS? Y=

Algebra ->  -> SOLUTION: GRAPH THE LINE: Y-5=3X. YOU MUST SHOW A TABLE WITH AT LEAST THREE X-Y VALUES. LABEL TH AXES AND SOME "HASH" MARKS. I GOT THESE BUT I STILL DON'T UNDERSTAND HOW TO DO THIS? Y=      Log On

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 Click here to see ALL problems on Graphs Question 72976: GRAPH THE LINE: Y-5=3X. YOU MUST SHOW A TABLE WITH AT LEAST THREE X-Y VALUES. LABEL TH AXES AND SOME "HASH" MARKS. I GOT THESE BUT I STILL DON'T UNDERSTAND HOW TO DO THIS? Y=5+3X X=(Y-5)/3 THANKS TO WHOEVER HELPS ME :)Answer by bucky(2189)   (Show Source): You can put this solution on YOUR website!A little more standard way of writing the equation is: . y = 3x + 5 . Your version was correct, but it's a little more conventional to write it this way. . Now the thing to do is just pick values for x, and use the equation to calculate the corresponding value for y. Finally you plot the points and then use a straight edge to draw a line through them. That will complete the graph. . Example 1. Let x = 0. Usually a good choice because it makes terms drop out or become much simpler. In this equation when x = 0 the term 3x goes away and the answer becomes y = 5. . On the coordinate system this would be the point x = 0 and y = 5. Notice that this would be on the y-axis up 5 units. Mark that point. [A standard way for identifying this point is (0, 5) where the first number is the x value and the second number is the y value.] . Next example. Pick another value for x. Maybe x = +2. Substitute that value for x in the equation . . When you do you get. So another point on the graph is where x = 2 and the corresponding y value is 11 or just simply (2, 11). . For a third point try letting x equal -5. Then use the equation to find the corresponding value of y: . . This point is (-5, -10) . You now have three points that should line up so that you can use a straight edge to draw a line through them all and in both directions. When you get done your graph should look something like this: . . Hope this helps you to understand the problem now.