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4x^2-5 < 8x
4x^2-8x-5=0 Change equation to equal to zero temporarily.
4*-5=-20, two factors of -20 whose sum is -8 are -10 and +2.
x=5/2, x=-1/2 These are the x intercepts on the graph. We have to test the equation on the second line above and below the intercepts to find where y<0
So y is negative between -1/2 and 5/2.