# SOLUTION: Can anyone help with the following problelm? Determine the vertex of the parabola. f(x) = x2 - 10x + 26

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 Click here to see ALL problems on Graphs Question 441503: Can anyone help with the following problelm? Determine the vertex of the parabola. f(x) = x2 - 10x + 26 Found 2 solutions by Alan3354, stanbon:Answer by Alan3354(34679)   (Show Source): You can put this solution on YOUR website!f(x) = x^2 - 10x + 26 ----------- The vertex is on the line of symmetry The line of symm is x = -b/2a x = 10/2 = 5 f(5) = 25 - 50 + 26 = 1 Vertex at (5,1) ------------------ Another method: f(x) = x^2 - 10x + 26 f'(x) = 2x - 10 = 0 x = 5 f(5) .... as above Answer by stanbon(60778)   (Show Source): You can put this solution on YOUR website!Can anyone help with the following problelm? Determine the vertex of the parabola. f(x) = x^2 - 10x + 26 --- 2 Methods: complete the square and use a formula. ------------------------------ Vertex occurs where x = -b/(2a) = 10/(2*1) = 5 f(x) = 5^2-10*5+26 = 1 --------------------------- Vertex: (5,1) =============== Cheers, Stan H. ===============