# SOLUTION: WRITE THE EQUATION OF THE LINE IN SLOPE-INTERCEPT FORM. PASSING THROUGH THE POINTS (-1,5),(-3,-2)

Algebra ->  -> SOLUTION: WRITE THE EQUATION OF THE LINE IN SLOPE-INTERCEPT FORM. PASSING THROUGH THE POINTS (-1,5),(-3,-2)      Log On

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 Click here to see ALL problems on Graphs Question 163060: WRITE THE EQUATION OF THE LINE IN SLOPE-INTERCEPT FORM. PASSING THROUGH THE POINTS (-1,5),(-3,-2)Answer by joecbaseball(37)   (Show Source): You can put this solution on YOUR website!Remember that the slope-intercept form is when the line is represented in the form: Y = mx + b, where m is the slope and b is the y-intercept. Now let’s figure what those values are: First of all, your slope (m) is the ratio of the difference in the y terms divided by the difference in the x terms, or, as some teachers say, “the rise over the run”. You have your two points, (-1,5), (-3,-2) The difference in your y terms is (5 – (-2)) = 7 The difference in your x terms is ((-1) – (-3)) = 2 So, your slope (m) is 7/2. Now plug that term into the generic slope-intercept form of the equation: y = (7/2)x + b. We now have to solve for b, and we have two different point coordinates to choose from. I’ll use (-1, 5) Putting (-1) in for x, and 5 in for y, we get: 5 = (7/2)(-1) + b, and solve for b. This gives us that b = 17/2. So the equation of the line for any point on the line is: y = (7/2)x + (17/2). Good luck