SOLUTION: Solve the problem. Assume that the sales of a certain appliance dealer are approximated by a linear function. Suppose that sales were \$11,000 in 1982 and \$47,000 in 1987. Let x=0

Algebra ->  -> SOLUTION: Solve the problem. Assume that the sales of a certain appliance dealer are approximated by a linear function. Suppose that sales were \$11,000 in 1982 and \$47,000 in 1987. Let x=0       Log On

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 Click here to see ALL problems on Graphs Question 123810This question is from textbook college Algebra : Solve the problem. Assume that the sales of a certain appliance dealer are approximated by a linear function. Suppose that sales were \$11,000 in 1982 and \$47,000 in 1987. Let x=0 represent 1982. Find the equation giving yearly sales S(x).This question is from textbook college Algebra Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!Assume that the sales of a certain appliance dealer are approximated by a linear function. Suppose that sales were \$11,000 in 1982 and \$47,000 in 1987. Let x=0 represent 1982. Find the equation giving yearly sales S(x). ----------------- You have two points (0,11000) and (5,47000) ----------- slope = (47000-11000)/(5-0) = 7200 ----------------------- form is y = mx+b; you know m, y, and x; solve for b b=11000 --------- S(x) = 7200x + 11000 ======================== Cheers, Stan H.