Tutors Answer Your Questions about Geometry proofs (FREE)
Question 238704: Question: Write Equations of the line that passes through the given points in point-slope form and slope-intercept form.
Problem: x-intercept is -6 ; y-intercept is 2
Point-slipe form:_______________
Slope-intercept form:__________
Click here to see answer by College Student(505)  |
Question 242229: I have a proof and shown is quadrilateral ABCD. On the figure the diagonals AC and DB are drawn. The point where they intersect is marked X. The givens are that AB and DC are parallel and that AC bisects BD. And I need to prove that figure ABCD is a parallelogram. I also need to set it up in the standard proof column order with statements on one side and reasons on the other. Thank you!
Click here to see answer by solver91311(16897)  |
Question 243006: I would like to solve the unknown angles of a trapezoid? I know the legs of the equal sided trapezoid and the angles total 180 degrees on each side (total 360 degrees, both sides). The top portion is 10.75" and bottom portion is 58.75" and each side leg 39.75". What are those angles and how do you solve?
thanks, Larry
Click here to see answer by Edwin McCravy(8912)  |
Question 246872: Write a two column proof. Given: line LJ bisects triangle LKJ and triangle LMJ. Prove: triangle LKJ = triangle LMJ
Given- angle K and angle M are right angles.
I don't understand two column proofs.
What I have so far is this:
LJ=LJ Given
angle K is a right angle given
angle M is a right angle given
and I think the ending is the HL postulate.
Thank you so much!
Click here to see answer by Jeff Gordon(65) |
Question 248317: I need to make a 2 column proof for geometry to prove that, the diagonals of a rectangle are congruent. My only given statement, is that 'abcd' is a rectangle. What steps do I need for the proof to prove it true? Thanks so much.
Click here to see answer by richwmiller(9143)  |
Question 248692: Hi! I am really stumped on this geometry question. I will try my best to explain the problem without a diagram.
I am asked to write a two-column proof. Given is isosceles trapezoid ABCD, with the top and bottom bases (AD and BC) being parallel. There is a line extending from angle D to point E, point E appearing to be the midpoint of BC. This line makes the left leg of triangle EDC, and it is given that DE is congruent to DC. I have to prove that ABED is a parallelogram.
I have tried several methods, and just when I think I'm solving the problem, I realize something is missing. I would really appreciate your help. Thank you.
Click here to see answer by richwmiller(9143)  |
Question 249738: Use the coordinate plane, the figure below, coordinate proof strategies, and the lengths and slopes of and to verify this theorem:
Given: QUAD is a quadrilateral.
P, G, R, M are the midpoints of the sides
Prove: The polygon formed by joining adjacent midpoints of a quadrilateral is a parallelogram.
http://i1021.photobucket.com/albums/af336/mattconley2011/1.jpg
Click here to see answer by math1745(1) |
Question 250767: Hi I am a geometry student in need of dire help. I am really confused with a couple of proofs here is are a few examples. If you could get back to me with a 2 column proof for them I would be extremely grateful.
1) ABCD is a parallelogram with angle A acute. A line from B is perpendicular to AD at E, and a line from D is perpendicular to BC at F. AF cuts BE at H, and CE cuts DF at K. Prove EHFK is a parallelogram
2) E is any point on side DC of parallelogram ABCD. DC is extended through C to F, so CF=DE. AE is extended through E to G so EG=AE. Prove EGFB is a parallelogram
Click here to see answer by dabanfield(803) |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890
|