Tutors Answer Your Questions about Geometry proofs (FREE)
Question 640484: 1. name two different ways to continue each pattern
~a,b,c....z
~a,z,b...
2.seven people meet and shake hands with one another
~using inductive reasoning write a formula for the number of handshakes if the number of people is n.
3.the fibonacci sequqnce consists of the pattern 1,1,2,3,5,8,13...
~what is the ninth term in the pattern?
~using a calculator look at the succesive ratios of one term to the next.make a conjecture.
~list the first eight terms of the sequence formed by finding the differences of succesive terms in the fibonacci sequence.
Click here to see answer by solver91311(16897)  |
Question 642658: The question is:
Can you think of any way to prove from Euclid's postulates that for every line l
(a) There exists a point lying on l?
(b) There exists a point not lying on l?
I'm thinking it has something to do with Euclid's parallel postulate, but I'm not sure. I have never written proofs before, so I am just having a difficult time trying to formulate this properly. Any help would be appreciated. Thank you!
Click here to see answer by jim_thompson5910(28598) |
Question 643016: I need help solving this proof,
PQ 5 RS. Prove PR 5 QS ____________________
P Q R S
Professor gave us this much
1.PQ=RS given
2.QR=QR Reflexive property
3.
4.
5.PR=QS
We are to do 3,4,5 and give reason, I have no clue how to do this. Help!
Click here to see answer by solver91311(16897)  |
Question 649444: Please answer these questions: I NEED IT NOW ASAP PLS PLS PLS I BEG YOU.
* http://static.tumblr.com/o5ekeuz/2OOma6taj/abc.png
and * http://static.tumblr.com/o5ekeuz/hBhma6td6/abcc.png
PLEASE THANKS I NEED IT NOW
Click here to see answer by lynnlo(4164) |
Question 649460: PLEASE OPEN THIS LINKS. SO THEY ARE LINK PLS OPEN THEM. Please answer these questions: THEY ARE LINKS SO PLEASE OPEN THEM.
* http://static.tumblr.com/o5ekeuz/2OOma6taj/abc.png
and * http://static.tumblr.com/o5ekeuz/hBhma6td6/abcc.png
PLEASE THANKS I NEED IT NOWI NEED IT NOW ASAP PLS PLS PLS I BEG YOU.
Click here to see answer by Alan3354(30993)  |
Question 652981: A_____B_____C_____D_____E Given: AC=CE AB=DE Prove: BC=CD 9 steps
1-AC=CE Given
2-AB=DE Given
3-AC=AB+BC Seg. Add. Post.
4-CE=CD+DE Seg. Add. Post.
5-AC=CB+DE Sub. Prop.
6-AB+BC=CD+DE Sub Prop.
7-AB+BC=CB+AB Sub Prop
8-BC=CD Sub Prop.
9-?
What am I missing or not understanding?
Click here to see answer by Shana-D77(122)  |
Question 652981: A_____B_____C_____D_____E Given: AC=CE AB=DE Prove: BC=CD 9 steps
1-AC=CE Given
2-AB=DE Given
3-AC=AB+BC Seg. Add. Post.
4-CE=CD+DE Seg. Add. Post.
5-AC=CB+DE Sub. Prop.
6-AB+BC=CD+DE Sub Prop.
7-AB+BC=CB+AB Sub Prop
8-BC=CD Sub Prop.
9-?
What am I missing or not understanding?
Click here to see answer by cholbrook74(1) |
Question 656367: For Each proof Identify the hypothesis, argument, and conclusion.
Given: AB = BC
Prove: AC = 2BC
Statement Reason
1 AB = BC Given
2 AB + BC = AC Segment Addition Postulate
3 BC + BC = AC Substitution Property of Equality
4 2BC = AC Distributive Property
5 AC = 2BC Identity
Do I write a hypothesis, argument, and conclusion for each statement?
Click here to see answer by solver91311(16897)  |
Question 656722: Hi! so I have this to be proven: I have an illustration of this square
upper left corner: L
upper right corner: O
lower left corner: V
Lower right corner: E
Given: LOVE is a square
Prove: Diagonals bisect each other
I dont really know how to do it, or to place ASA postulate, or right angles,... dont know i dont get it please help me understand, I will have a test next week. help me please thank you
Click here to see answer by lynnlo(4164) |
Question 657289: Needing help understanding proof.
Statements
1. CD is perpendicular to CE
2. Angle DCE is a right angle
3. ?
4. M Angle DCE = m angle 1 + m angle2
5. ?
6. <1 and <2 are complementary
Reasons
1. Given
2. ?
3. Def. of a right angle
4. Addition ?
5. Subsitution
6. Congruent Complements ?
Click here to see answer by MathLover1(6649)  |
Question 659031: complete each proof
given: BC+DE
Prove: AB+DE=AC
Proof:
Statement Reasons
BC=DE ___________
__________ Seg. Add. Post.
AB+DE=AC ____________
Given: Q is between P and R, R is between Q and S, PR=QS
Prove: PQ=RS
Statements Reasons
Q is between P and R given
PQ+QR=PR ________________
R is between Q ans S ________________
___________________ Seg. Add. Post.
PR=QS ________________
PQ+QR=QR+RS ________________
PQ+QR-QR=QR+RS-QR ________________
_________________ Substitution
I need help please answer by today if you can
Click here to see answer by MathLover1(6649)  |
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