SOLUTION: Construct a truth table for ~(p ∨ r) ↔ (~q ∧ ~r)

Algebra.Com
Question 990738: Construct a truth table for
~(p ∨ r) ↔ (~q ∧ ~r)
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!

  p   q    ~q   r    ~r    (p ∨ r)   ~(p ∨ r)    (~q ∧ ~r)      ~(p ∨ r) ↔ (~q ∧ ~r)
___________________________________________________________________________________________________________

  T | T  |  F | T  |  F   |    T    |     F     |     F      |             T
  T | T  |  F | F  |  T   |    T    |     F     |     F      |             T
  T | F  |  T | T  |  F   |    T    |     F     |     F      |             T
  T | F  |  T | F  |  T   |    T    |     F     |     T      |             F
  F | T  |  F | T  |  F   |    T    |     F     |     F      |             T
  F | T  |  F | F  |  T   |    F    |     T     |     F      |             F
  F | F  |  T | T  |  F   |    T    |     F     |     F      |             T
  F | F  |  T | F  |  T   |    F    |     T     |     T      |             T

John

My calculator said it, I believe it, that settles it

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