Let ABCD be a trapezoid with the bases AB and DC, and AC and BD be its diagonals. (Figure 1). We need to prove that the triangles Let us draw the altitudes AE and BF in the trapezoid ABCD from vertices A and B to the base DC (Figure 1). Notice that these altitudes are congruent as the opposite sides of the rectangular ABFE. Now, the triangles congruent altitudes to the base. Therefore, these triangles have the same area. |
Figure 1 |