SOLUTION: Given: parallelogram XYZW; angle X=80 degrees Prove: parallelogram XYZW is not a rectangle

SOLUTION: Given: parallelogram XYZW; angle X=80 degrees Prove: parallelogram XYZW is not a rectangle

Algebra.Com

Question 948770: Given: parallelogram XYZW; angle X=80 degrees
Prove: parallelogram XYZW is not a rectangle
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
A rectangle has 4 angles that are each equal to 90 degrees.
For XYZW,

Since XYZW has angles 80,100,80,100, it is not a rectangle.

RELATED QUESTIONS
Find the coordinates of the intersection of the diagonals of parallelogram XYZW with... (answered by Fombitz)

given: ACDF is a parallelogram, angle AFB= angle ECD prove: FBCE is a... (answered by MRperkins)

How do I find the coordinates of the intersection of the diagonals of Parallelogram XYZW... (answered by Fombitz)

Given Parallelogram RSTW and XYTZ prove angle R is congruent to angle... (answered by ikleyn)

Given: Quadrilateral ABCD is a parallelogram. Angle C is a right angle.... (answered by ad_alta)

Given: ABCD is a parallelogram with m < A = m < D. Prove: ABCD is a rectangle (answered by ikleyn)

My question on my homework says " Find the coordinates of the intersection of the... (answered by robertb)

Find the coordinates of the intersection of the diagonals of parallelogram XYZW with... (answered by josgarithmetic,MathTherapy)

Given: ABCD is a parallelogram Prove: angle DAB is congruent to... (answered by richwmiller)