SOLUTION: <a rel=nofollow HREF="http://tinypic.com?ref=65yb2b" target="_blank"><img src="http://i59.tinypic.com/65yb2b.jpg" border="0" alt="Image and video hosting by TinyPic"></a>

Algebra.Com
Question 934336: Image and video hosting by TinyPic
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
Image and video hosting by TinyPic

angle CDE = Angle CED ( Given)
Therefore CD congruent - CE ( converse of Isosceles angle theorem)
But CD = BE given
Therefore CE = BE
Therefore angle ECB = angle EBC ( isosceles angle theorem)........(1)
In triangle CED angle CEB = angle ECD + angle EBC ( exterior angle theorem)
Therefore angle CEB = 2 angle EBC ( angle ECB = angle EBC ) from (1)
angle DCA + angle DAC = angle CDE ( exterior angle theorem)
But angle CDE =angle CED ( Isosceles Triangle)
angle DCA + angle DAC=angle ECD + angle EBC = 2angle B
Therefore angle CED = angle DCA + angle DAC =2 angle B
Therefore angle A = angle B
Therefore AC = BC ( converse of isosceles angle theorem

RELATED QUESTIONS

(answered by josgarithmetic)
Please help me with this proof: (answered by AnlytcPhil)
(answered by MathLover1)
(answered by ikleyn)
(answered by Fombitz)
(answered by josgarithmetic,math_helper)
(answered by algebrahouse.com)
(answered by Alan3354)
(answered by ikleyn)