SOLUTION: the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find the ordinate of point p
Algebra.Com
Question 926255: the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find the ordinate of point p
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find the ordinate of point p
------
That is really old terminology.
abscissa is the x-value
ordinate is the corresponding y-value
Your point is (-6,y)
---------------
Equation:
(y-3)^2 + (-6-1)^2 = 74
----
(y-3)^2 + 49 = 74
-----
(y-3)^2 = 25
---
y-3 = 5 or y-3 = -5
y = 8 or y = -2
------------------
Cheers,
Stan H.
---------------
RELATED QUESTIONS
The sum of the distance from a point P to (8,0) and (-8,0) is 20. If the abscissa of P is (answered by josgarithmetic)
The ordinate of a point P is twice the abscissa. The point is equidistant from (-3,1) and (answered by Alan3354)
distance formula Analytic Geometry
The sum of the distance from a point P to (8,0) and... (answered by josgarithmetic)
Find the point whose distance from (7, -3) is √58 and whose abscissa equals its... (answered by KMST)
The ordinate of a point which is √29 units from (5,1) is twice its abscissa. Find... (answered by sachi)
find the point whose distance from (7,-3) is square root of 58 and whose abscissa equals... (answered by richwmiller)
find the point whose distance from (7,-3) is square root of 58 and whose abscissa equals (answered by solve_for_x)
P(x,2x)
The ordinate of a point P is twice the abscissa. This point is equidistant... (answered by Theo)
The abscissa of a point is -6 and its distance from the point (1,3)is square root 74.... (answered by stanbon)