SOLUTION: You are given the information that triangle ABC has an altitude of CD. Then you have to write a paragraph proof stating that the Sin A/a = Sin B/b.

Question 855017: You are given the information that triangle ABC has an altitude of CD. Then you have to write a paragraph proof stating that the Sin A/a = Sin B/b.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
If angles A and B are acute, altitude CD divides the triangle, into two right triangles:

In those right triangles, the trigonometric ratios involving altitude CD and angles A and B are
<-->
<-->

If one of the angles A and B is obtuse, sides AC and BC, along with altitude CD, and the line containing AB form two right triangles:
Ray BD is the extension of AB. Obtuse angle ABC is called angle B for short.
Angle B and angle CBD are supplementary and therefore have the same sine.
In right triangles ADC and BDC, the trigonometric ratios involving altitude CD and angles A and B are
<-->
<-->

In either case, and ,
so
Dividing both sides of the equal sign by we get

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