SOLUTION: Please prove the following identity
1-(cosx-sinx)^2=sin2x
I attempted it but I only get as far as opening the brackets. And I'm not even sure if I'm doing that correct. Please
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-> SOLUTION: Please prove the following identity
1-(cosx-sinx)^2=sin2x
I attempted it but I only get as far as opening the brackets. And I'm not even sure if I'm doing that correct. Please
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Question 827723: Please prove the following identity
1-(cosx-sinx)^2=sin2x
I attempted it but I only get as far as opening the brackets. And I'm not even sure if I'm doing that correct. Please help.. Answer by Edwin McCravy(20081) (Show Source):
1-[cos(x)-sin(x)]ē = sin(2x)
To square a binomial write it twice and use FOIL:
1-[cos(x)-sin(x)][cos(x)-sin(x)]
1-[cosē-cos(x)sin(x)-sin(x)cos(x) + sinē(x)]
The two terms in the middle are the same
so they add together:
1-[cosē(x)-2sin(x)cos(x) + sinē(x)]
Since cosē(x)+sinē(x)=1
1-[1-2sin(x)cos(x)]
1-1+2sin(x)cos(x)
2sin(x)cos(x)
Since sin(2x) = 2sin(x)cos(x)
sin(2x)
Edwin